1. Tardigrade
  2. Question
  3. Chemistry
  4. Assertion: The major products formed by heating C6H5CH2OCH3 with HI are C6H5CH2I and CH 3OH. Reason: Benzyl cation is more stable than methyl cation

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Q. Assertion : The major products formed by heating
$C_6H_5CH_2OCH_3$ with $HI$ are $C_6H_5CH_2I \, and \, CH_ 3OH. $
Reason : Benzyl cation is more stable than methyl cation

AIIMSAIIMS 2004Alcohols Phenols and Ethers

Solution:

Reaction of $III$ with $C _{6} H _{5} CH _{2} OCH _{3}$ follow $SE ^{1}$ mechanism which lead to the formation of carbonium ion. Benzyl cation is more stable than methyl cation, so it is formed as the intermediate which leads to the formations of $C _{6} H _{5} CH _{2} I$ and $CH _{3} OH$.
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