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Q. Assertion: The formal oxidation no. of sulphur in $Na_2S_4O_6$ is 2.5.
Reason: Two S-atoms are not directly linked with O-atoms.

AIIMSAIIMS 2011Redox Reactions

Solution:

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Formal oxidation number of sulphur

$=\frac{2 \times 5+2 \times 0}{4}=2.5$