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Q. Assertion : The error in the measurement of radius of the sphere is $0.3 \%$.The permissible error in its surface area is $0.6 \%$.
Reason : The permissible error is calculated by the formula $\frac{\Delta A }{ A }=\frac{4 \Delta r }{ r }$

Physical World, Units and Measurements

Solution:

Area $A =4 \pi r^2$
Fractional error $\frac{\Delta A}{A}=\frac{2 \Delta r}{r}$
$\frac{\Delta A}{A} \times 100=2 \times 0.3 \%=0.6 \%$