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Q. Assertion : Smaller drops of liquid resist deforming forces better than the larger drops.
Reason : Excess pressure inside a drop is directly proportional to its surface area.

AIIMSAIIMS 2004Mechanical Properties of Fluids

Solution:

Also excess pressure inside a bubble is
image
$P=\frac{4 T}{R}$
where $R$ is radius of bubble.
Since excess pressure is inversely proportional to radius, hence excess pressure inside a smaller drop is large as compared to larger drop due to which smaller drop resists deforming forces better than a larger drop
Also
$P=\frac{4 T}{R} $
$P \propto \frac{1}{\Delta A}$
Also $ P=\frac{4 T}{R}=\frac{4 W}{R \cdot \Delta A} $
$\left(\because T=\frac{W}{\Delta A}\right)$
$\Rightarrow P \propto \frac{1}{\Delta A}$
Hence, excess pressure is inversely proportional to surface area.