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Q. Assertion: $NO_3^-$ is planar while $NH_3$ is pyramidal.
Reason: $N$ in $NO_3^-$ is $sp^2$ and in $NH^3$ is $sp^3$ hybridized.

AIIMSAIIMS 1997The p-Block Elements - Part2

Solution:

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Hybridisation is $sp^2$ here and therefore planar structure is expected.

$NH^3 : 1s^2 , 2s^2 , 2p^3$

Hybridisation is $sp^3$ , therefore tetrahedral structure is expected but there is pyramical structure as lone pair of electron occupy one of the corners of tetrahedral.

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