Q.
Assertion $Na^{+}$ and $Al^{3+}$are isoelectronic but the magnitude of ionic radius of $Al^{3+}$ is less than that of $Na^{+}$.
Reason The magnitude of effective nuclear charge of the outer shell electrons in $Al^{3+}$ is greater than that in $Na^{+}$.
AIIMSAIIMS 2013
Solution: