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Q. Assertion: $N _{2}$ and $NO ^{+}$ both are diamagnetic substance.
Reason: $NO ^{+}$ is isoelectronic with $N _{2}$.

AIIMSAIIMS 1997Structure of Atom

Solution:

Due to the absence of unpaired electron in $NO ^{+}$ and $N _{2}$, both are diamagnetic

image

total no. of $e ^{-}$ in $NO =6+8=14$

total no. of $e ^{-}$ in $N _{2}=7+7=14$

Thercfore, both are isoelectronic.