Q.
Assertion $N _{3}^{-}$is a weaker base than $NH _{2}^{-}$.
Reason The lone pair of electrons on $N$ atom in $N _{3}^{-}$is in a $s p^{2}$-orbital while in $NH _{2}^{-}$it is in an $s p^{3}$-orbital.
AIIMSAIIMS 2010
Solution: