Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Assertion Magnitude of resultant of two vectors may be less than the magnitude of either vector.
Reason Vector addition is commutative.

Motion in a Plane

Solution:

Resultant of two vectors $A$ and $B$ is given as
$R=\sqrt{A^{2}+B^{2}+2 A B \cos \theta}$
$\therefore$ We can say that
(i) If $\theta$ is an obtuse angle, then magnitude of $R$ will be less than magnitude of the either vectors $A$ or $B$.
e.g. if $| A |=4,| B |=3 $ and $\theta=120^{\circ} $, then
$| R |=\sqrt{4^{2}+3^{2}+2 \times 4 \times 3 \cos \left(120^{\circ}\right)} $
$=\sqrt{25-12}=\sqrt{13} \left(\because \cos 120^{\circ}=-\frac{1}{2}\right)$
$\therefore | R | < | A |$
(ii) If the vectors are in opposite direction and are equal in magnitude, then also the magnitude of $R$ will be less than the magnitude of either vectors $A$ or $B$.
e.g., if $| A |=| B |=a$ (say) and $\theta=180^{\circ}$
then,
$| R | =\sqrt{a^{2}+a^{2}-2 a^{2} \cos \left(180^{\circ}\right)} $
$=\sqrt{2 a^{2}-2 a^{2}} \left[\because \cos 180^{\circ}=-1\right]$
$\therefore | R | < | A | $ or $| B |$
Also, vector addition is commutative in nature.
$A + B = B + A$
Therefore, Assertion and Reason are correct but Reason is not the correct explanation of Assertion.