Q.
Assertion : In YDSE, if $I _1=9 I _0$ and $I _2=4 I _0$ then $\frac{ I _{\max }}{ I _{\min }}=25$.
Reason : In YDSE $I_{\max }=\frac{1}{2}\left(\sqrt{I_1}+\sqrt{I_2}\right)^2$ and $I _{\min }=\frac{1}{2}\left(\sqrt{ I _1}-\sqrt{ I _2}\right)^2$.
Wave Optics
Solution: