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Q. Assertion In the $E2$ elimination, $\beta$ - $H$ and leaving group should be antiperiplanar.
Reason In the $E2$ elimination, base always abstracts unhindered $\beta- H$.

AIIMSAIIMS 2010

Solution:

In $E2$ elimination, $\beta$ - $H$ and leaving group are in the same plane but anti-conformation. Base can abstract hindered $\beta$-H. Thus, Reason is false.