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Q. Assertion In the E2 elimination, $ \beta -H $ and leaving group should be antiperiplanar. Reason In the E2 elimination, base always abstracts hindered $ \beta -H. $

VMMC MedicalVMMC Medical 2012

Solution:

In $ E2 $ elimination, $ \beta -H $ and leaving group are in the same plane but anti-conformation. Base can abstract hindered $ \beta -H. $