Q.
Assertion : In high spin situation, configuration of of $d^{5}$ ions will be $t^{3}_{2g}e^2_{g}$.
Reason : In high spin situation, pairing energy is less than crystal field energy.
Solution:
$\therefore 4$ In high spin situation, $\Delta_{0} < P,$ in $d^5$ configuration, $4^{th}$ and $5^{th}$ electron are added to $e_{g}$ rather than $t_{2g}$ So configuration of $d^5$ ion will be $t^3_{2g} e^2_{g}$