Q.
Assertion H-S-H bond angle in H$_2$S is closer to 90$^{\circ}$ but H-0-H bond angle in H$_2O$ is 104.5$^{\circ}$.
Reason $lp-lp$ repulsion is stronger in $H_2S$ than in H$_2O$.
Chemical Bonding and Molecular Structure
Solution: