Q.
Assertion : $[Fe(H_2O)_5NO]SO_4$ is paramagnetic.
Reason : The $Fe$ in $[Fe(H_2O)_5NO]SO_4$ has three unpaired electrons.
Solution:
Fe+ : [Ar] 3d6 4s1
When the weak field ligand H2O and strong field ligand NO attack, the configuration changes as follows:
Fe+ : [Ar] 3d7 4s0
∴ Fe+ has 3 unpaired electrons.
