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Q. Assertion: Cu is stronger reducing agent than $H_2$.
Reason: E$^{\circ}$ of $Cu^{2+}/Cu$ is negative.

AIIMSAIIMS 2013Redox Reactions

Solution:

$: E^{\circ}$ of $Cu ^{2+} / Cu$ is $+0.34\, V$ and positive $E^{\circ}$ means that the redox couple is a weaker reducing agent than the $H ^{+} / H _{2}$ couple.