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Q. Assertion : $Al(OH)_3$ is insoluble in $NH_4OH$ but soluble in $NaOH$ .
Reason : $NaOH$ is strong alkali

The p-Block Elements

Solution:

$Al(OH)_3$ is soluble in strong alkali like $NaOH$ because of formation of meta-aluminate ion
$NaOH + Al(OH)_3 \rightarrow NaAlO_2 + 2H_2O$