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Q. Assertion A safe turn by a cyclist should neither be fast nor sharp.
Reason The bending angle from the vertical would decrease with increase in velocity.

AIIMSAIIMS 2010

Solution:

For safe turn $\tan \theta \geq \frac{v^{2}}{r g}$
It is clear that for safe turn $v$ should be small and $r$ should be large. Also bending angle from the vertical would increase with increase in velocity.