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Q. Assertion (A) Higher order ionisation constant $\left(K_{a_{2}}, K_{a_{3}}\right)$ are smaller than the lower order ionisation constant $\left(K_{a_{1}}\right)$ of a polyprotic acid.
Reason (R) It is more difficult to remove a positively charged proton from a negative ion due to Coulombic forces.

Equilibrium

Solution:

Higher order ionisation constants $\left(K_{a_{2}}, K_{a_{3}}\right)$ are smaller than the lower order ionisation constant $\left(K_{a_{1}}\right)$ of a polyprotic acid. The reason for this is that, it is more difficult to remove a positively charged proton from a negative ion due to electrostatic forces.
This can be seen in the case of removing a proton from the uncharged $H _{2} CO _{3}$ as compared from a negatively charged $HCO _{3}^{-}$.
Thus, $A$ is correct but $R$ is incorrect.