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Q. Assertion : A body of mass $1\, kg$ is making $1 \,rps$ in a circle of radius $1\, m$. Centrifugal force acting on it is $4 \pi^{2} N$.
Reason : Centrifugal force is given by $F=\frac{m v^{2}}{r}$

AIIMSAIIMS 2008

Solution:

From relation
$F =\frac{m v^{2}}{r}=\frac{m(r \omega)^{2}}{r}=m r \omega^{2} $
$=m r(2 \pi v)^{2} 4 \pi^{2} m r v^{2}$
Here, $m=1 \,kg v=1 \,rps , r=1\, m$
$\therefore F=4 \pi^{2} \times 1 \times 1 \times 1^{2}=4 \pi^{2} N$