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Q. Assertion $(A)$ A charge $q$ is placed on a height $h / 4$ above the centre of a square of side $b$. The flux associated with the square is independent of side length.
Reason $(R)$ Gauss's law is independent of size of the Gaussian surface.

AIIMSAIIMS 2015

Solution:

In this problem, the concept of electric flux is applied.
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We can assume the charge is placed at the centre of the cube. The flux through all the six faces according to the Gauss's law is $\frac{q}{\varepsilon_{0}}$.
Thus, flux through one face is $\frac{1}{6}\left(\frac{q}{\varepsilon_{0}}\right)$.
Which is independent of size of the cube.