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Q. Asserion (A):$f(x)=|x-a|+|x-b|$, is continous on $R$
Reason(R): $\frac{|x-\alpha|}{x-\alpha} 0$ is continuous at $x \in R-\{\alpha\}$

TS EAMCET 2020

Solution:

The function $f(x)=|x-a|+|x-b|$ is continuous on $R$
The function $\frac{|x-\alpha|}{x-\alpha}$ is continuous at $x \in R-\{\alpha\}$