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Q. As you can seen from Fig. (i) and (ii) shows refraction of light from air to glass and from air to water. Find out the value of the angle $\theta$ in the case of refraction as shown in figure (iii) will bePhysics Question Image

Ray Optics and Optical Instruments

Solution:

${ }^{a} \mu_{g}=\frac{\sin 50^{\circ}}{\sin 40^{\circ}}\,\,\,...(i)$
${ }^{a} \mu_{w}=\frac{\sin 50^{\circ}}{\sin 45^{\circ}}\,\,\,...(ii)$
${ }^{w} \mu_{g}=\frac{\sin 45^{\circ}}{\sin \theta}\,\,\,...(iii)$
${ }^{a} \mu_{w} \times{ }^{w} \mu_{g}={ }^{a} \mu_{g}$
$\frac{\sin 50^{\circ}}{\sin 45^{\circ}} \times \frac{\sin 45^{\circ}}{\sin \theta}=\frac{\sin 50^{\circ}}{\sin 40^{\circ}} $
( Using Eq. (i), (ii) and (iii)
$ \sin \theta =\sin 40^{\circ} $
$ \theta =40^{\circ}$