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Q. As shown in figure, the tension in the horizontal cord is $30 \, N.$ The weight $w$ and tension in the string $OA$ in newton are

Question

NTA AbhyasNTA Abhyas 2020Laws of Motion

Solution:

Horizontal and vertical components of tension are shown in the figure.
Solution
From the figure, $Tsin 30^{o} = 30$ .....(i)
$Tcos 30^{o} = w$ .....(ii)
By solving Equations (i) and (ii), we get
$w=30\sqrt{3} \, N$
and $T=60 \, N$