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Q. As a result of change in the magnetic flux linked to the closed loop shown in figure, an emf, $V$ volt is induced in the loop. The work done (in joule) in taking a charge $q$ coulomb once along the loop is
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Electromagnetic Induction

Solution:

Work done in taking a charge $= Q$
Volt induced in the loop $= V$
Work done in moving a test charge $Q$ and a loop having induced emf $E$,
will be QE $\therefore $ As the induced electric field due to change in magnetic field is non-conservative.
The work done due to change will become $W = QV$
Hence, The work done (in joule) in taking a charge $Q$ column once along the loop is $QV$