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Q. Arrangement of two block system is as shown. The net force acting on $1\, kg$ and $2\, kg$ blocks are (assuming the surfaces to be frictionless) respectivelyPhysics Question Image

Laws of Motion

Solution:

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acceleration of the system $=\frac{F_{\text {ext }}}{M_{\text {Total }}}$
$=\frac{6}{3}=2\, m / s ^{2}$
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for $2 kg$ block
$N=2(2)=4\, N$
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for $1\, kg$ block
$F_{\text {net }}=6-4=2\, N$