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Q. Arrange the following in decreasing order of their boiling points:
(I) $n$-Butane
(II) $2$-Methylbutane
(III) $n$-Pentane
(IV) $2$,$2$-Dimethylpropane

Hydrocarbons

Solution:

Boiling point of alkanes increases with increase in molecular mass and for the same alkane the boiling point decreases with branching.
Thus, the decreasing order of their boiling points is :
$\underset{(III)}{n-\text{Pentane} >} \underset{(II)}{2-\text{Methylbutane} >}\underset{(IV)}{2,2-\text{Dimethylpropane} >} \underset{(I)}{n-\text{Butane}}$