1. Tardigrade
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  4. Arrange the following free radicals in order of decreasing stability Methyl (I), Vinyl (II), Allyl (III), Benzyl (IV)

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Q. Arrange the following free radicals in order of decreasing stability Methyl (I), Vinyl (II), Allyl (III), Benzyl (IV)

Delhi UMET/DPMTDelhi UMET/DPMT 2009

Solution:

On the basis of hyperconjugation the order of stability of given free radicals is as follows : $\underset{\text{benzyl F.r.}}{C_6H_5\overset{\bullet}{C}H_2} > CH_2 = \underset{\text{allyl F.r.}}{CH - \overset{\bullet}{C}H_2} > \underset{\text{methyl F. r.}}{\overset{\bullet}{C}H_3} > \underset{\text{Vinyl F.r.}}{CH_2 = \overset{\bullet}{C}H} $