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Chemistry
Arrange the following cyano complexes in decreasing order of their magnetic moment.
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Q. Arrange the following cyano complexes in decreasing order of their magnetic moment.
NTA Abhyas
NTA Abhyas 2020
Coordination Compounds
A
$\left[ Cr ( CN )_{6}\right]^{3-}>\left[ Mn ( CN )_{6}\right]^{3-}>\left[ Fe ( CN )_{6}\right]^{3-}>\left[ Co ( CN )_{6}\right]^{3-}$
28%
B
$\left[ Mn ( CN )_{6}\right]^{3-}>\left[ Cr ( CN )_{6}\right]^{3-}>\left[ Fe ( CN )_{6}\right]^{3-}>\left[ Co ( CN )_{6}\right]^{3-}$
9%
C
$\left[ Fe ( CN )_{6}\right]^{3-}>\left[ Cr ( CN )_{6}\right]^{3-}>\left[ Mn ( CN )_{6}\right]^{3-}>\left[ Co ( CN )_{6}\right]^{3-}$
52%
D
$\left[ Co ( CN )_{6}\right]^{3-}>\left[ Cr ( CN )_{6}\right]^{3-}>\left[ Mn ( CN )_{6}\right]^{3-}>\left[ Fe ( CN )_{6}\right]^{3-}$
10%
Solution:
$\left[ Cr ( CN )_{6}\right]^{3-} Cr ^{3+}$ in strong ligand field $= t _{2 g }^{3} e _{ g }^{0}=3$ unpaired electron
- $\left[ Mn ( CN )_{6}\right]^{3-} Mn ^{3+}$ in strong ligand field $= t _{2 g }^{4} e _{ g }^{0}=2$ unpaired electron
- $\left[ Fe ( CN )_{6}\right]^{3-} Fe ^{3+}$ in strong ligand field $= t _{2 g }^{5} e _{ g }^{0}=1$ unpaired electron
$\left[ Co ( CN )_{6}\right]^{3-} Co ^{3+}$ in strong ligand field $= t _{2 g }^{6} e _{ g }^{0}=0$ unpaired electron