1. Tardigrade
  2. Question
  3. Chemistry
  4. Arrange the following compounds in the increasing order of their boiling points. underset(I)CH 3 CH 2 CH 2 CHO , underset(II)CH 3 CH 2 CH 2 CH 2 OH , underset(III)H 5 C 2 O - C 2 H 5, undersetIVCH 3 CH 2 CH 2 CH 2 CH 3

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Q. Arrange the following compounds in the increasing order of their boiling points.
$\underset{(I)}{CH _{3} CH _{2} CH _{2} CHO} , \,\,\, \underset{(II)}{CH _{3} CH _{2} CH _{2} CH _{2} OH} ,$
$\underset{(III)}{H _{5} C _{2} O - C _{2} H _{5}}, \,\,\,\, \underset{IV}{CH _{3} CH _{2} CH _{2} CH _{2} CH _{3}}$

Aldehydes Ketones and Carboxylic Acids

Solution:

The boiling point of butan- $1-o l$ would be highest, due to extensive intermolecular hydrogen bonding. Butanal is more polar than ethoxyethane. The intermolecular dipole-dipole attraction is stronger in the butanal. $n$-pentane molecules have only weak van der Waals'forces. The increasing order of boiling point of the given compounds are
$IV < III < I < II$