1. Tardigrade
  2. Question
  3. Chemistry
  4. Arrange the following carbanions in order of their decreasing stability. (I) H3C - C ≡ C- (II) H - C ≡ C- (III) H3C - CH-2

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Q. Arrange the following carbanions in order of their decreasing stability.
$\left(I\right) H_{3}C - C \equiv C^{-}$
$\left(II\right) H - C \equiv C^{-}$
$\left(III\right) H_{3}C - CH^{-}_{2}$

Hydrocarbons

Solution:

The order of decreasing stability of carbanions is:
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$sp$-hybridised carbon atom is more electronegative than $sp^3$-hybridised carbon atom and hence, can accommodate the negative charge more effectively. $— CH_3$ group has $+I$ effect, therefore, it intensifies the negative charge and hence, destabilises the carbanion

Solution Image