1. Tardigrade
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  3. Chemistry
  4. Aromatization of n -heptane by passing over ( Al 2 O 3+. .Cr 2 O 3) catalyst at 773 K gives

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Q. Aromatization of $n$ -heptane by passing over $\left( Al _{2} O _{3}+\right.$ $\left.Cr _{2} O _{3}\right)$ catalyst at $773 K$ gives

Hydrocarbons

Solution:

Correct answer is (c) Toluene

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