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  4. Area of triangle whose vertices are (x1, y1),(x2, y2) and (x3, y3), is

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Q. Area of triangle whose vertices are $\left(x_1, y_1\right),\left(x_2, y_2\right)$ and $\left(x_3, y_3\right)$, is

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Solution:

Area of the triangle, whose vertices are $\left(x_1, y_1\right),\left(x_2, y_2\right)$ and $\left(x_3, y_3\right)$, is $\frac{1}{2}\left|x_1\left(y_2-y_3\right)+x_2\left(y_3-y_1\right)+x_3\left(y_1-y_2\right)\right|$