1. Tardigrade
  2. Question
  3. Mathematics
  4. Area of the triangle whose vertices are (4,4),(3,-2) and (-3,16), is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Area of the triangle whose vertices are $(4,4),(3,-2)$ and $(-3,16)$, is

Straight Lines

Solution:

Area of the triangle, whose vertices are $(4,4),(3,-2)$ and $(-3,16)$
$=\frac{1}{2}|4(-2-16)+3(16-4)+(-3)(4+2)| $
$=\frac{|-72+36-18|}{2}$
$ =\frac{|-54|}{2}=\frac{54}{2}=27$