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  4. Area of the triangle formed by the vertex, focus and one end of latusrectum of the parabola (x+2)2=-12(y-1) is

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Q. Area of the triangle formed by the vertex, focus and one end of latusrectum of the parabola $(x+2)^2=-12(y-1)$ is

Conic Sections

Solution:

Consider equal parabola $y^2=12 x$.
Vertex: $V(0,0)$
Focus: $S(3,0)$
End point of Latus Rectum: $A(3,6)$
$\therefore $ Required area $=\frac{1}{2} S V \times A S=9$ sq. units