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Q. Area of the curve $x^{2}+y^{2}=2 a x$ is

KCETKCET 2022

Solution:

By L.H. Rule, given $=\underset{x \rightarrow 0}{lt}\left[\frac{\frac{1}{3+x}-\frac{1}{3-x}}{1}\right]=\frac{1}{3}+\frac{1}{3}=\frac{2}{3}$