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Q.
Area of a parallelogram two of whose sides are given by $2 x^{2}-5 x y+2 y^{2}=0$ and one of its diagonal is $5 x+2 y=1$, is
Straight Lines
Solution:
$\therefore $ Area of parallelogram
$=2 \left(\frac{1}{2}\begin{vmatrix}0&0&1\\ \frac{1}{9}&\frac{2}{9}&1\\ \frac{2}{12}&\frac{1}{12}&1\end{vmatrix}\right)=\frac{1}{36} \,s$
