Question

Area lying in the first quadrant between the curves $x^{2}+y^{2}=\pi ^{2}$ and $y=sinx$ , is equal to

• A. $\frac{\left(\left(\pi \right)^{2} - 8\right)}{2}$
• B. $\frac{\left(\left(\pi \right)^{3} - 8\right)}{3}$
• C. $\frac{\left(\left(\pi \right)^{2} - 8\right)}{4}$
• D. $\frac{\left(\left(\pi \right)^{3} - 8\right)}{4}$

Answer 1

Answer: (D)

Area the circle in $1^{st}$ quadrate. $=\pi .\frac{\pi ^{2}}{4}$
Area of one loop of $sinx=2$
$\frac{\pi ^{3}}{4}-2=\frac{\pi ^{3} - 8}{4}$