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Q. Area enclosed by the graph of $y =\ln ( x +1)$, $y$-axis, and the line $y =1$ is

Application of Integrals

Solution:

$\left.A=\int\limits_0^1\left(e^y-1\right) d y=e^y-y\right]_0^1$
image
$= (e - 1) - (1 - 0)$
$= e - 2$