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Q.
Area bounded by the curve $y=\log x$ and the coordinate axes is
Application of Integrals
Solution:
Observing the graph of $\log x$, we find that the required area lies below $x$ -axis between $x=0$ and $x=1$.
So required area $=\left|\int\limits_{0}^{1} \log x d x \right|$
$=|(x \log x-x)|_{0}^{1}=|-1|=1$
