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Q.
Area bounded by lines y = 2 + x, y = 2 - x and x = 2 is:
Application of Integrals
Solution:
Given y = 2 + x and y = 2- x
By solving these, we get x = 0
Now, the required area = $\int^2_0 y \, dx$
$ = \int^2_0 [(2 + x) - (2-x)]dx$
$ = \int^2_0 (0+2x)dx = 2 . \frac{x^2}{2} \bigg|^2_0 = 2 . \frac{4}{2} = 4 $