Question

Approximately, the temperature corresponding to 1 eV energy, is

• A. $7.6 \times 10^{2} K$
• B. $7.7 \times 10^{3} K$
• C. $7.1 \times 10^{3} K$
• D. $7.2 \times 10^{3} K$

Answer 1

Answer: (B)

Given: Energy $(E)=1 eV =1.6 \times 10^{-19} \,J$.
Average kinetic energy per molecule $(E)=1.6 \times 10^{-19} \,J$
$=\frac{3}{2}\, k T$ or $ T=\frac{2 \times\left(1.6 \times 10^{-19}\right)}{3 k} $
$=\frac{2 \times\left(1.6 \times 10^{-10}\right)}{3 \times\left(1 \cdot 38 \times 10^{-21}\right)} $
$=7.7 \times 10' K$
(where $k$ is Boltzman constant $=1.38 \times 10^{-23}$.