Question

Anon-ideal solution was prepared by mixing $30\, mL$ chloroform and $50\, mL$ acetone. The volume of mixture will be :

• A. > 80 mL
• B. < 80 mL
• C. = 80 mL
• D. $\ge$ 80 mL

Answer 1

Answer: (B)

Chloroform and acetone form a non-ideal solution in which A...B type interaction are more than A.. A and B...B type interaction due to H-bonding. Hence, the solution shows, negative deviation from Raoult's law, i.e.,
$ \Delta {{V}_{mix}}=-ve;\Delta {{H}_{mix}}=-ve $ $ \therefore $ total volume of solution = less than (30 + 50 mL) or < 80 mL