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  4. Angular width (β) of central maximum of a diffraction pattern on a single slit does not depend upon

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Q. Angular width $(\beta)$ of central maximum of a diffraction pattern on a single slit does not depend upon

Wave Optics

Solution:

For single slit diffraction pattern
$d \sin \theta=\lambda(d=$ slit width $)$
Angular width $=2 \theta=2 \sin ^{-1}\left(\frac{\lambda}{d}\right)$
It is independent of $D$ i.e. distance between screen and slit.