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Physics
Angular momentum of earth revolving around the sun in a circular orbit of radius R is proportional to
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Q. Angular momentum of earth revolving around the sun in a circular orbit of radius $R$ is proportional to
KEAM
KEAM 2015
Gravitation
A
$\sqrt{R}$
45%
B
R
7%
C
$R^2$
16%
D
$R^{1/2}$
25%
E
$R^{3/2}$
25%
Solution:
We know that angular momentum of Earth
$L=m v R$
$\Rightarrow \, L=m \sqrt{\frac{G M}{R}} \times R$
$\Rightarrow \, L \propto R^{1 / 2}$