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Q. Angular momentum of earth revolving around the sun in a circular orbit of radius $R$ is proportional to

KEAMKEAM 2015Gravitation

Solution:

We know that angular momentum of Earth
$L=m v R$
$\Rightarrow \, L=m \sqrt{\frac{G M}{R}} \times R$
$\Rightarrow \, L \propto R^{1 / 2}$