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Q. Angle between two vectors $(\hat{i}+\hat{j})$ and $(\hat{i}-\hat{j})$ is

Motion in a Plane

Solution:

$\cos \,\theta=\frac{(\hat{i}+\hat{j}) \cdot(\hat{i}-\hat{j})}{|\hat{i}+\hat{j} \| \hat{i}-\hat{j}|}=\frac{1-1}{\sqrt{2} \cdot \sqrt{2}}=0$
$\Rightarrow \theta=90^{\circ}$