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Q. An X-ray tube is operated at 2 million volt. The wavelength of the shortest wave produced will be around

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Solution:

Here, V = 2 \times 10^{6} V
\lambda_{\text{min}} = \frac{hc}{eV}
= \frac{6.6\times 10^{-34}\times 3\times 10^{8}}{1.6\times 10^{-19} \times 2\times 10^{6}}
= 6 \times 10^{-13} m
= 6\times 10^{-3}\mathring{A}