Question

An urn contains 2 red, 4 white and 6 blue baalls. Three balls are drawn one by one without replacement. Three events $E, F$ and $G$ are defined as $E$ : no two of the 3 drawn balls is red. $F$ : no two of the 3 drawn balls is white. $G$ : no two of the 3 drawn balls is blue. then which one of the following is correct ?

• A. $P ( E )= P ( F )= P ( G )$
• B. P(E) $<$ P(F) $<$ P(G)
• C. P(G) $<$ P(F $)<$ P(E)
• D. P(G) $<$ P(E) $<$ P(F)

Answer 1

Answer: (C)

Correct answer is (c) P(G) $<$ P(F $)<$ P(E)