Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. An unknown metal of mass $192\, g$ heated to a temperature of $100^{\circ}C$ was immersed into a brass calorimeter of mass $128\, g$ containing $240 \,g$ of water at a temperature of $8.4^{\circ}C$. Calculate the specific heat (in $J \,kg^{-1} K^{-1})$ of the unknown metal if water temperature stablizes at $21.5^{\circ}C$. (Specific heat of brass is $394\, J \,kg^{-1} K^{-1})$

Thermal Properties of Matter

Solution:

Let specific heat of unknown metal be ‘$s$’ According to principle of calorimetry, Heat lost
= Heat gain $m \times S\Delta \theta = m_1 S_{\text{brass}} (\Delta \theta_1 + m_2 S_{\text{water}} + \Delta \theta_2)$
$\Rightarrow 192 \times S \times (100-21.5)$
$= 128 \times 394 \times (21.5 -8.4)$
Solving we get, $+ 240 \times 4200 \times (21.5 - 8.4)$
$S = 916\,Jkg^{-1} k^{-1}$