1. Tardigrade
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  3. Chemistry
  4. An unknown compound D first oxidized to aldehyde and then acetic acid by a dilute solution of K 2 Cr 2 O 7 and H 2 SO 4. The compound D is

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Q. An unknown compound $D$ first oxidized to aldehyde and then acetic acid by a dilute solution of $K _{2} Cr _{2} O _{7}$ and $H _{2} SO _{4}$. The compound $D$ is

Bihar CECEBihar CECE 2007

Solution:

$D\xrightarrow{\text{Oxidation}}$ aldehyde $\xrightarrow[{ H _{2} SO _{4}}]{ K _{2} Cr _{2} O } \underset{\text { Acetic acid }}{ CH _{3} COOH }$
$1^{\circ}$ alcohol on oxidation gives aldehyde having same number of carbon and aldehyde on oxidation gives acid having same number of carboñ atoms. It means, $D$ will be alcohol having two carbon atoms that is $C _{2} H _{5} OH$ (ethyl alcohol) and the alcohol on oxidation will give $CH _{3} CHO$ (acetaldehyde)
$\underset{(D)}{C _{2} H _{5} O H} \xrightarrow{\text { [O] }} CH _{3} CHO \xrightarrow{[ O ]} CH _{3} COOH$